Jumblah Lima Suku Pertama Deret Geometri 4+12+36​

Pertanyaan : jumblah lima suku pertama deret geometri 4+12+36​

Jawaban :
a = 4[tex]r = \frac{u2}{u1} = \frac{12}{4} = 3[/tex]Jumlah 5 suku pertama (S5) [tex]sn = \frac{a( {r}^{n} – 1)}{r – 1} \\ s5 = \frac{4( {3}^{5} – 1)}{3 – 1} \\ s5 = \frac{4(243 – 1)}{2} \\ s5 = 2(242) \\ s5 = 484[/tex][tex]\colorbox{FAFAD2}{\tt{\colorbox{EE82EE}{✿\:Riskafrebianti\:(RiBel)\:✿}}}[/tex]

Originally posted 2023-01-03 04:38:40.