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Jawaban : PendahuluanLingkaran adalah bentuk yang terdiri dari semua titik dalam bidang yang berjarak tertentu dari titik tertentuRumus Lingkaranπ / phi = 3,14 atau 22/7 Luas = πr²/π × r × rKeliling v1 = 2 × π × гKeliling v2 = π x dr = d ÷ 2d = r × 2d = diameterr = jari jariPembahasan SoalA.L = 154 cm²Luas Lingkaran= πr²154 = 22/7 × r × rr² = 154 ÷ 22/7r² = 154 × 7 ÷ 22r² = 49r = √49r = 7 cmd = 14 cmB.314 cm²(π = 3,14)Luas Lingkaran= πr²314 = 3,14 × r × rr² = 314 ÷ 3,14r² = 100r = √100r = 10 cmd = 20 cmC.L = 616 cm²Luas Lingkaran= πr²616 = 22/7 × r × rr² = 616 ÷ 22/7r² = 616 × 7 ÷ 22r² = 196r = √196r = 14 cmd = 28 cmD.L = 1.256 cm²(π = 3,14)Luas Lingkaran= πr²1.256 = 3,14 × r × rr² = 1.256 ÷ 3,14r² = 400r = √400r = 20 cmd = 40 cmE.L = 1.386 cm²Luas Lingkaran= πr²1.386 = 22/7 × r × rr² = 1.386 ÷ 22/7r² = 1.386 × 7 ÷ 22r² = 441r = √441r = 21 cmd = 42 cmF.L = 3.850 cm²Luas Lingkaran= πr²3.850 = 22/7 × r × rr² = 3.850 ÷ 22/7r² = 3.850 × 7 ÷ 22r² = 1.225r = √1.225r = 35 cmd = 70 cm

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